[PyKDE] problem with custom signals

[Eron Lloyd]

On Wednesday 08 March 2006 4:35 am, Phil Thompson wrote:
> On Wednesday 08 March 2006 8:08 am, Emanuele Santos wrote:
> > Hi, Phil
> >
> > I'm using the latest version of PyQt4 (20060306) and when I try something
> > like:
> >
> > self.emit(QtCore.SIGNAL("mySignal(PyObject *)", myObject)
> >
> > I get a type error, but if I use the short-circuited version
> >
> > self.emit(QtCore.SIGNAL("mySignal"), myObject)
> >
> > it works fine.
> >
> > In your e-mail (couple weeks ago) I thought both ways were supposed to
> > work, am I correct?
>
> Yes, it's a bug. Will be fixed in tonight's SIP snapshot.

Hi all,

I'm trying to port code to PyQt4, and am having trouble implementing the new 
signal/slot convention. I did my best to try and follow the previous list 
discussions, but I still can't seem to get it to work. I wrote a test script 
that provides the kind of behavior I'm needing, basically custom python 
signals (and type arguments) passed to Qt built-in slots. I'm using SIP 
4.4.1, yesterday's PyQt4 snapshot, and Qt 4.1.2. Thanks for any pointers!


from PyQt4.QtCore import *
from PyQt4.QtGui import *

a = QApplication([])

w = QMainWindow()
m = QWidget()
w.setCentralWidget(m)
l = QGridLayout(m)
t = QTreeWidget(m)  # The "view" to be toggled
t.setHeaderLabels(["One", "Two"])
b1 = QPushButton("Enable", m)
b2 = QPushButton("Disable", m)

l.addWidget(t, 0, 0, 1, 2)
l.addWidget(b1, 1, 0)
l.addWidget(b2, 1, 1)

def enable():
    print "Enabling view..."
    m.emit(SIGNAL("enableView"), True)  # pass to t.setEnabled(True)

def disable():
    print "Disabling view..."
    m.emit(SIGNAL("disableView"), True)  # pass to t.setDisabled(True)

m.connect(b1, SIGNAL("clicked()"), enable)
m.connect(b2, SIGNAL("clicked()"), disable)
m.connect(m, SIGNAL("enableView"), t, SLOT("setEnabled(bool)"))
m.connect(m, SIGNAL("disableView"), t, SLOT("setDisabled(bool)"))

if __name__ == '__main__':
    w.show()
    a.exec_()