[PyKDE] More QWidget queries.

[Andreas Pakulat]

On 13.09.06 21:26:51, Dave S wrote:
> I now have my widget appearing on screen in a modal fashion thanks to Andreas
> 
> f1 = form1(self)
> if f1.exec() == QDialog.Accepted:
> 	script ...
> else:
> 	script ...
> 
> However this only allows the communication of two states from the widget, 
> either accept() or close() so I can only really have an OK button (accept) 
> and a quit button (close).
> 
> Is there a way to signal a third state for a third button ? My GUI would be 
> far more logical if it were possible.

Not in the way above. For that to happen you'd need to connect each
button to a separate slot. Inside the slots you set a member variable
which reflects the button that was pressed (i.e. an int with values
0,1,2 depending on the button) and just call close() after that. This
will close the dialog. When calling the dialog you just do:

f1.exec()

without any if's around it. Following that you can check the value of
the member variable

if f1.buttonPressed == 0:
  script_for_ok_button
else if f1.buttonPressed == 1:
  script_for_cancel_button
...

Andreas

-- 
Never give an inch!