[PyQt] multiple signal connect

[Daniel Miller]

Try this:

for button in [...]:
     def slot():
         self.button_clicked(button)
     button.__slot = slot # keep a reference so it doesn't get GC'd
     QtCore.QObject.connect(..., slot)


~ Daniel




On Aug 20, 2008, at 11:17 AM, Ruben Fonseca wrote:

> Hi,
>
> I'm having a problem developing my first Python Qt4 app and I thought
> you could help me.
>
> I have a bunch of buttons that I want to watch for the "clicked()"
> signal.
>
> Since the handling is the same for all buttons I decided to write
> something like this
>
> ----------
> for button in [self.button_1, self.button_2, ..., self.button_0]:
>    QtCore.QObject.connect(button, QtCore.SIGNAL('clicked()'), lambda:
> self.button_clicked(button))
>
> def button_clicked(self, number):
>    print "Received a signal from %s" % number.objectName()
> ----------
>
> However, every time I click on a button I got on the console
>
> "Received a signal from button_0"
>
> regardless the button I click... So I'm guessing something's wrong  
> with
> my lambda function.
>
> What's the best way of solving this particular problem in Python?
>
> Thank you for you support
> Ruben Fonseca
> _______________________________________________
> PyQt mailing list    PyQt at riverbankcomputing.com
> http://www.riverbankcomputing.com/mailman/listinfo/pyqt