[PyQt] Bug in QRectF

[David Lassonde]

Yes. The goal here is to join two bounding boxes so the resulting bounding box is the union of the two rectangles.

as documented in the Qt reference (http://doc.trolltech.com/4.5/qrect.html#operator-7c):

	QRect QRect::operator| ( const QRect & rectangle ) const
	Returns the bounding rectangle of this rectangle and the given rectangle.

	See also operator|=() and united().

	QRect & QRect::operator|= ( const QRect & rectangle )
	Unites this rectangle with the given rectangle.


The rectangles I am using are limit cases. Here are some results with trivial rectangles (good results)

from PyQt4.QtCore import QRectF
goodRect = QRectF(0,0,1,3000) | QRectF(0,0,0,16)
#	(0.0, 0.0, 1.0, 3000.0)


from PyQt4.QtCore import QRectF
goodRect = QRectF(0,0,1,3000) | QRectF(0,0,0,16)
#	(4.0, 5.0, 11.0, 11.0)



-----Original Message-----
From: pyqt-bounces at riverbankcomputing.com [mailto:pyqt-bounces at riverbankcomputing.com] On Behalf Of Henrik Pauli
Sent: Friday, July 24, 2009 9:34 AM
To: pyqt at riverbankcomputing.com
Subject: Re: [PyQt] Bug in QRectF

On Friday 24 July 2009 15:16:38 David Lassonde wrote:
> Hi all,
>
> the following does not work in PyQt 4.5.2:
>
> from PyQt4.QtCore import QRectF
> wrongRect = QRectF(0,0,0,3000) | QRectF(0,0,0,16)

Are you sure you mean the bitwise or here? :)

>
> The expected result is (0,0,0,3000) but I get (0,0,0,16).
>
> it used to work in PyQt 4.4.3
>
> As a workaround, I am now using my own "or" function.
>
> I thought you might be interested in the information.
>
> Cheers,
>
> David
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