[PyQt] Signal this way

pantheon animator333 at yahoo.com
Tue Sep 29 02:47:11 BST 2009


I am creating <QAction> in a loop and adding it to menu.

action = QtGui.QAction(QtGui.QIcon(iconFile), fileName, menu)

I need to connect this action to a python function in such a way that I
should get <text> of QAction or instance of QAction object itself.
Python function:

If action name is required

def contextMenuAction(self, actionName):
        print actionName

If action object is required

def contextMenuAction(self, actionObject):
        myData = actionObject.data()

How do I setup action and slot? Logically it would be like this:

self.connect(action, QtCore.SIGNAL("triggered()"), self,
QtCore.SLOT("contextMenuAction(str)"), fileName)
self.connect(action, QtCore.SIGNAL("triggered()"), self,
QtCore.SLOT("contextMenuAction(object)"), action)



Python 2.5.2
Win XP, 32 Bit 
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