[PyQt] using itemDoubleClicked with pyqt
Christopher M. Nahler
christopher.nahler at papermodels.at
Wed Jun 23 08:40:09 BST 2010
I have problems using a signal. In the code below I create a QListWidget
where I would like to act upon doubleClicking an item.
In the documentation I have found the signal "itemDoubleClicked".
(http://doc.qt.nokia.com/4.6/qlistwidget.html#itemDoubleClicked)
But somehow I am not using it right. What am I doing wrong?
thanks in advance
Chris
import sys
from PyQt4.QtCore import *
from PyQt4.QtGui import *
itemList = ["One",
"Two",
"Three",
"Four",
"Five"]
class ListDlg(QDialog):
def __init__(self, name, parent=None):
super(ListDlg, self).__init__(parent)
self.myList = QListWidget()
self.myList.addItems(itemList)
self.myList.setCurrentRow(0)
layout = QHBoxLayout()
layout.addWidget(self.myList)
self.setLayout(layout)
self.connect(self.myList, SIGNAL("itemDoubleClicked(*item)"),
self.processItem)
def processItem(self, item):
print(item.text())
if __name__ == "__main__":
app = QApplication(sys.argv)
form = ListDlg("Listdialog")
form.exec_()
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