[PyQt] Wrapping a scoped template type

[Phil Thompson]

On Sun, 21 Mar 2010 11:09:19 +0100, Philip Lorenz <lorenzph+sip at in.tum.de>
wrote:
> Hi,
> 
> I am trying to wrap a templated scoped type (in my case 
> std::set<T>::iterator) using SIP 4.10.0. However I have not yet managed 
> to find a solution which solves this case nicely.
> 
> According to the SIP reference templates must be of the form template 
> ::= scoped-name < type-list > which does not fit here.
> 
> I have tried to wrap the std::set<T> declaration using a typedef, i.e.:
> 
> typedef std::set<T> myset
> typedef myset::iterator mysetiterator
> 
> but this resulted in a myset is undefined error message.
> 
> Hence my current approach is to typedef the iterator to a void * for SIP 
> and mapping it to the real type inside a %ModuleHeaderCode:
> 
> %ModuleHeaderCode
> typedef std::set<MyType>::iterator MyTypeSetIterator;
> %End
> 
> typedef void * MyTypeSetIterator;
> 
> 
> Unfortunately this requires a patched SIP binary as the generated source 
> files refer to the type by void * (I am not using the /NoTypeName/ 
> annotation) rather than the name specified by the typedef.
> 
> I have attached the patch file against SIP which works around the issue 
> described above. However I would be very grateful if anyone knows how to 
> solve this issue in a nicer way.

Do you want to define a template to SIP, or are you only interested in the
<MyType> version?

If the latter then...

%ModuleHeaderCode
typedef std::set<MyType>::iterator MyTypeSetIterator;
%End

%MappedType MyTypeSetIterator
...
%End

If the former then the following might work...

%ModuleHeaderCode
typedef std::set<T>::iterator std::set_iterator<T>
%End

template<T>
%MappedType std::set_iterator<T>
...
%End

Phil