[PyQt] Sending a Signal from a QTableWidget header
Hans-Peter Jansen
hpj at urpla.net
Tue Jan 24 21:29:51 GMT 2012
On Tuesday 24 January 2012, 00:37:31 starglider.dev wrote:
> Hi Pete,
> thank you for your help.
> I found the anwser in Mark Summerfield's book:
Good choice.
> chapter 14 in file ships-delegate.pyw
> Here is the code:
> header = tableView.horizontalHeader()
> self.connect(header, SIGNAL("sectionClicked(int)"),
> self.sortTable)
Better use new style signals'n'slots:
header.sectionClicked.connect(self.sortTable)
Much easier, less typing and more secure, since it will traceback on
startup, if you fail to type the signal name correctly.
Pete
> jorge
>
> On 22 January 2012 15:57, Hans-Peter Jansen <hpj at urpla.net> wrote:
> > On Sunday 22 January 2012, 16:38:21 Hans-Peter Jansen wrote:
> > > On Saturday 21 January 2012, 23:21:18 starglider.dev wrote:
> > > > Hi,
> > > > I need to open a dialog if the user click in the QTableWidget
> > > > header.
> > >
> > > There's no such class in PyQt (nor in Qt). If you mean QTable,
> > > then QHeader.clicked() is proably, wat you're looking for.
> >
> > Scratch that, I looked up the wrong docs.
> >
> > Since QTableWidget inherits from QTableView, the
> > {horizontal,vertical}Header() methods return a QHeaderView
> > instance, which emits e.g. sectionPressed(int).
> >
> > Sorry for the confusion.
> >
> > Pete
> > _______________________________________________
> > PyQt mailing list PyQt at riverbankcomputing.com
> > http://www.riverbankcomputing.com/mailman/listinfo/pyqt
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