[PyQt] QPoint not automatically cast to QPointF

[Shriramana Sharma]

In my recent work with Beziers I ran across this. A QPoint is *not*
automatically converted into a QPointF in Python/PyQt while it *is*
converted in C++:

The following C++ code compiles fine:

# include <QtCore/QPoint>
# include <QtGui/QPainterPath>
int main ( void ) {
	QPainterPath p ;
	QPoint p1 ( 100, 150 ), c1 ( 166, 250 ), c2 ( 234, 250 ), p2 ( 300, 150 ) ;
	p . moveTo ( p1 ) ;
	p . cubicTo ( c1, c2, p2 ) ;
}

whereas its Python/PyQt equivalent:

#! /usr/bin/env python3
from PyQt4 . QtCore import QPoint
from PyQt4 . QtGui import QPainterPath
p = QPainterPath ()
p1 = QPoint ( 100, 150 )
c1 = QPoint ( 166, 250 )
c2 = QPoint ( 234, 250 )
p2 = QPoint ( 300, 150 )
p . moveTo ( p1 )
p . cubicTo ( c1, c2, p2 )

produces the following:

Traceback (most recent call last):
  File "./qpoint-test.py", line 11, in <module>
    p . moveTo ( p1 )
TypeError: arguments did not match any overloaded call:
  QPainterPath.moveTo(QPointF): argument 1 has unexpected type 'QPoint'
  QPainterPath.moveTo(float, float): argument 1 has unexpected type 'QPoint'

But QPointF in PyQt *does* provide a constructor from QPoint, so is
this the limitation of Python that it does not automatically check
whether it can convert one type to another to satisfy a function's
call signature? (Or is there some other fault in my PyQt code?)

I realize I could always convert it manually using QPointF(p1) etc but
the assumption seems natural that an integer-precision numeric object
should be accepted where a float-precision can...

-- 
Shriramana Sharma