[PyQt] QComboBox don't emit signal into a dialog box

[Vincent Vande Vyvre]

Le 17/10/2013 11:38, Phil Thompson a écrit :
> On Thu, 17 Oct 2013 11:20:43 +0200, Vincent Vande Vyvre
> <vincent.vandevyvre at swing.be> wrote:
>> When placed into a dialog box the QComboBox don't emit any signal if the
>> user activate it.
>>
>> When the current item is changed by the program, the signal is correctly
>> emitted.
>>
>> Python 2.7,  Qt: 4.8.1,  PyQt: 4.9.1
>> Python 3.2,  Qt: 4.8.1,  PyQt: 4.9.1
>>
>> Example
>>
>> from PyQt4 import QtGui
>>
>> class Editor(object):
>>       def __init__(self, Dial):
>>           super(Editor, self).__init__()
>>           self.grid = QtGui.QGridLayout(Dial)
>>           self.cmb = QtGui.QComboBox(Dial)
>>           self.grid.addWidget(self.cmb, 0, 0, 1, 1)
>>           self.cmb.addItems(['One', 'Two', 'Three'])
>>           self.cmb.currentIndexChanged.connect(self.index_changed)
>>           self.cmb.activated.connect(self.index_changed)
>>           self.btn = QtGui.QPushButton('Quit', Dial)
>>           self.grid.addWidget(self.btn, 1, 0, 1, 1)
>>           self.btn.clicked.connect(Dial.accept)
>>
>>           self.cmb.setCurrentIndex(1)
>>
>>       def index_changed(self, idx):
>>           print('Index:', idx)
>>
>> app = QtGui.QApplication([])
>> Dial = QtGui.QDialog()
>> Editor(Dial)
>> reply = Dial.exec_()
>>
>> With Qt: 5.0.2 + PyQt: 5.0 no problem, that's works.
> Keep a reference to your Editor instance.
>
> Phil
>
You'r right, that's works.

Strange behavior ...

Thank's

@ Sebastian, no, object or QObject don't change anything.

-- 
Vincent V.V.
Oqapy <https://launchpad.net/oqapy> . Qarte 
<https://launchpad.net/qarte> . PaQager <https://launchpad.net/paqager>