[PyQt] Exception propagation in the exec_() loop

[Bryan A. Jones]

Yuya,

Thanks -- that was exactly what I needed! The revised, working code:

import sys
from PyQt4.QtCore import QTimer
from PyQt4.QtGui import QApplication

def af():
    assert False

def main():
    sys.excepthook = lambda type, value, traceback: app.quit()
    app = QApplication(sys.argv)
    QTimer.singleShot(0, af)
    app.exec_()

if __name__ == '__main__':
    main()


Bryan


On Fri, Jan 24, 2014 at 5:25 AM, Yuya Nishihara <yuya at tcha.org> wrote:

> On Thu, 23 Jan 2014 13:43:32 -0600, Bryan A. Jones wrote:
> > It seems that exceptions which occur in an event loop (when calling
> > app.exec_(), for instance) are caught and printed, but not passed on. Is
> > there any way to allow exceptions to propagate past exec_()? As a
> concrete
> > example, the following code prints the following backtrace, but doesn't
> > exit.
> >
> > import sys
> > from PyQt4.QtCore import QTimer
> > from PyQt4.QtGui import QApplication
> >
> > def af():
> >     assert False
> >
> > def main():
> >     app = QApplication(sys.argv)
> >     QTimer.singleShot(0, af)
> >     app.exec_()
>
> You can install sys.excepthook for uncaught exceptions.
>
> http://docs.python.org/2.7/library/sys.html#sys.excepthook
>
> Regards,
>



-- 
Bryan A. Jones, Ph.D.
Associate Professor
Department of Electrical and Computer Engineering
231 Simrall / PO Box 9571
Mississippi State University
Mississippi state, MS 39762
http://www.ece.msstate.edu/~bjones
bjones AT ece DOT msstate DOT edu
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fax 662-325-2298

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