[PyKDE] Getting cell coordinates in QTable's contextMenuEvent (code snippet included).

[kgi]

Hi there.

I'm adding a context menu to a QTable widget, and am trying to work out which 
cell has received the context menu event. I'm using the approach given in the 
code snippet below.

I was originally stumped that the coordinates received by contextMenuEvent() 
didn't seem to reflect the table being scrolled, but I found a workaround 
based upon [1].

Now my problem is that the row/col system seems to be asymmetrical; that is:

(all clicks are 'right' clicks):

 - clicking on the vertical header reports 'row = 0'
 - clicking on the row labelled '1' reports 'row = 1'

But:

 - clicking on the horizontal header reports 'col = 0'
 - clicking on the column labelled '1' reports 'col = 0'
 - clicking in the last row (labelled '40') reports 'row = -1'

Does anyone have any idea why this is the case and what the 'right' way to 
work around it would be?

Thanks,

Ricky

=======================================================

import sys

from qt import *
from qttable import QTable

class MyTable ( QTable ):

    def __init__ ( self, *args ):
        QTable.__init__ ( self, *args )

        
    def contextMenuEvent ( self, cmev ):
        cmev.accept()
        x = cmev.x()
        y = cmev.y()

        xoffset =  + self.horizontalHeader().offset()
        yoffset =  + self.verticalHeader().offset()

        col = self.columnAt ( x + xoffset )
        row = self.rowAt ( y + yoffset )

        print "X: ", x
        print "Y: ", y
        print "Xoff: ", xoffset
        print "Yoff: ", yoffset
        print "col: ", col
        print "row: ", row


if __name__ == '__main__':

    numRows = 40
    numCols = 5

    app = QApplication ( sys.argv )
    table = MyTable ( numRows, numCols )

    table.show()
    app.setMainWidget ( table )
    app.exec_loop()

==========================================================

[1] http://lists.trolltech.com/qt-interest/2002-01/thread00017-0.html